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5x^2+55x=900
We move all terms to the left:
5x^2+55x-(900)=0
a = 5; b = 55; c = -900;
Δ = b2-4ac
Δ = 552-4·5·(-900)
Δ = 21025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{21025}=145$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-145}{2*5}=\frac{-200}{10} =-20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+145}{2*5}=\frac{90}{10} =9 $
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